res[i] = stack.length ? cur - stack[stack.length - 1] : cur;
Multi-platform optimization
'Why I have to go to a secret school'，详情可参考PDF资料
You are friends with all the senior TLs, so can get them to review your code, but this is not a high-leverage use of time.，推荐阅读电影获取更多信息
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